Notices by curved-ruler (curved_ruler@mastodon.gamedev.place)

@aral what

Is there a tool something like that shady speedtest.net?

@clarity happy birthday! would you like a meme?

Yep I thought it is Lorentz attractor.

looks good, but wrong

more like it

New toy, Lorenz (v0)
https://curved-ruler.github.io/webgl-sketches/lorenz/lorenz.html

x+cos(x) is stable

Added a Rössler system
Also, x+10cos(x) is not stable

return [x + 1*Math.cos(y)*Math.sin(z),
y + 1*Math.cos(z)*Math.sin(x),
z + 1*Math.cos(x)*Math.sin(y)];

@woozong terasology, minetest, but if their friends play minecraft, no alternative will do

@mcc
https://merveilles.town/@prahou/112247017144832938

let a = 2.0*Math.sin(x/4.0)*Math.cos(y/4.0);
let b = 2.0*Math.sin(y/4.0)*Math.cos(z/4.0);
let c = 2.0*Math.sin(z/4.0)*Math.cos(x/4.0);
return a*b-c;

vec3 col(in float x, in float y)
{
vec2 z = vec2(x,y);
int i = 0;
int n = 64;
for (i=0 ; i<n ; ++i)
{
vec2 z5 = cmul(z,cmul(z,z));
vec2 a = (z5-vec2(pow(0.3976,3.0), 0.0));
vec2 b = (z5+vec2(pow(0.7638,3.0), 0.0));
vec2 c = (z5+vec2(pow(0.6625,3.0), 0.0));
z = 0.72*cdiv(a,cdiv(b,cdiv(c,z)));
if (length(z) > 100.0) break;
}
float t = fract(float(i) / float(n)*16.0);
return hsv2rgb(vec3(0.1, 0.9, t));
}

vec3 col(in float x, in float y)
{
vec2 z = vec2(x,y);
int i = 0;
int n = 64;
for (i=0 ; i<n ; ++i)
{
vec2 z5 = cmul(z,cmul(z,cmul(z,cmul(z,cmul(z,z)))));
vec2 a = (z5-vec2(pow(0.3976,2.0), 0.0));
vec2 b = (z5+vec2(pow(0.7638,2.0), 0.0));
vec2 c = (z5+vec2(pow(0.6625,2.0), 0.0));
z = 0.72*cdiv(a,cdiv(b,cdiv(c,z)));
if (length(z) > 100.0) break;
}
float t = fract(float(i) / float(n)*16.0);
return hsv2rgb(vec3(0.1, 0.9, t));
}

vec3 col(in float x, in float y)
{
vec2 z = vec2(x,y);
int i = 0;
int n = 64;
for (i=0 ; i<n ; ++i)
{
vec2 z5 = cmul(z,cmul(z,cmul(z,cmul(z,z))));
vec2 a = (z5-vec2(1.0, 0.0));
vec2 b = (z5+vec2(1.0, 0.0));
vec2 c = (z5+vec2(pow(0.6625,5.0), 0.0));
z = cdiv(a,cdiv(b,cdiv(c,z)));
if (length(z) > 20.0) break;
}
float t = fract(float(i) / float(n)*16.0);
return hsv2rgb(vec3(0.1, 0.9, t));
}

zooming to the Planck length

Pic by @olafurw