Notices by Wanderer über dem Nebelmeer (wandereruber@poa.st)
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Wednesday, 30-Sep-2026 05:49:17 JST
Wanderer über dem Nebelmeer
Slytherin my dick into Malfoids pussy -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Wednesday, 30-Sep-2026 05:49:15 JST
Wanderer über dem Nebelmeer
@kaia kaia do you not think that malfoid is hot I would have thought it to be right up your alley -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Wednesday, 02-Sep-2026 05:42:28 JST
Wanderer über dem Nebelmeer
@theorytoe who me? I don't know anything I'm retarded -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Wednesday, 02-Sep-2026 05:41:32 JST
Wanderer über dem Nebelmeer
@theorytoe pretty cool man, thanks -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Wednesday, 02-Sep-2026 05:34:20 JST
Wanderer über dem Nebelmeer
@theorytoe mfw Shadow the Hedgehog pisses on my FUCKING wife -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Wednesday, 02-Sep-2026 04:05:48 JST
Wanderer über dem Nebelmeer
@theorytoe @Aether I did that. Keep coming back to needing my own harness and benchmark suite though, to get better at getting better code -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Wednesday, 02-Sep-2026 03:51:05 JST
Wanderer über dem Nebelmeer
@theorytoe @Aether Rember that coding challenge? Muse Spark failed. After multiple tries. With screenshots and debugging capabilities.
Muse spark scores 62 on aa coding index. Opus 5 has 68. -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Wednesday, 02-Sep-2026 03:47:24 JST
Wanderer über dem Nebelmeer
@Aether you know, I am generally really pro AI, pro vibe-coding even. I like it, it's fun, it's useful.
But I am getting really tired of this
>LLMs have gotten very good at generating code
They have? Show me. Show me the good code they produce. Show me the before. Explain the problem. Show me their solution.
Because from where I'm standing, I'm seeing people produce 2 pages of text for a skill that explicitly explains to these "smarter than a PhD" systems that they should check if this functionality is in the std lib or an existing dependency, instead of reinventing the wheel.
And whenever I peer under the hood in my projects, I have no fucking idea what any of the code is supposed to do. There's comments everywhere that tell me nothing. And it doesn't do it anyways. -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Wednesday, 02-Sep-2026 02:42:33 JST
Wanderer über dem Nebelmeer
@Nils "hag sex" -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Tuesday, 01-Sep-2026 23:45:18 JST
Wanderer über dem Nebelmeer
@lain >dHH
coincidence? I think not -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Tuesday, 01-Sep-2026 23:10:47 JST
Wanderer über dem Nebelmeer
@lain >Omarchy is the software arm of a fascist project
Must.Not.Gigaquote... -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Tuesday, 01-Sep-2026 21:26:39 JST
Wanderer über dem Nebelmeer
Senior Software Engineer at the Kellogg's company getting fired for bringing up "deserialization" in a meeting -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Tuesday, 01-Sep-2026 10:14:26 JST
Wanderer über dem Nebelmeer
*Master Chief voice*
only Halo ring I care about is the one I'm putting on Cortana's finger -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Monday, 31-Aug-2026 04:40:52 JST
Wanderer über dem Nebelmeer
@bajax @theorytoe right direction.
hints:
you have a grid[x][y] for the ids already
you don't need to return the grid lines where you would draw a border, you can just draw a line to the screen at the position you want it. -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Monday, 31-Aug-2026 04:40:50 JST
Wanderer über dem Nebelmeer
@bajax @theorytoe iterate array over x and y
inside the for loop you have access to
square[x][y] and therefore also square[x+1][y] etc.
yes you do have to check the segment but you don't need to keep a mental map of them you can just decide if you have to draw or not -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Monday, 31-Aug-2026 03:05:40 JST
Wanderer über dem Nebelmeer
@theorytoe >the goal is to take grouped squares
this is what you keep getting wrong lol
you think there are islands of squares and you have to outline them that's far more complicated than what the actual task is -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Monday, 31-Aug-2026 02:47:24 JST
Wanderer über dem Nebelmeer
@theorytoe it's very very insightful for me because it tells me what I suspect every single day of my life: Nobody ever understands what the fuck I'm saying.
I'm making a version for you to play around with right now. JS though, sorry. challenge said "common, but unfamiliar language" :) -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Monday, 31-Aug-2026 02:37:02 JST
Wanderer über dem Nebelmeer
@theorytoe yes it would look like that and id_loc[x][y] == 0 means unoccupied
Interesting that you think the problem is this complicated to solve. Or I didn't explain clearly, or am misunderstanding your solution because it is too elegant for my grugdev brain.
"border" = " a line drawn on a grid edge. There is no requirement to do this in one drawing operation or anything like that. The end result is all that counts.
There's just two requirements: there must be a line around the area as a whole ( "draw a border around the data structure")
and
there must be a line on the grid edge between adjacent squares if they are neither siblings nor parent/child.
Like I said, I might be misunderstanding, but scanning an entire row or column and deriving some information from that is not necessary for this.
The fact that you think it's something more complicated makes me question if that was perhaps the issue for the AI as well -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Monday, 31-Aug-2026 01:49:01 JST
Wanderer über dem Nebelmeer
@theorytoe Because you know how to ask questions, you would obviously find this information in the codebase very easily.
>group these datastructures based on if the squares share a common ancestor?
not quite. there is one single data structure and this is drawn to the screen as squares. This area is always contiguous and has no holes. They occupy an area of the grid. one cell ("square) per node. Each square (node in the data structure) has an id an a parentid.
you are supposed to draw a border around the structure as a whole, and on the edges between squares that are neither siblings nor parent/child.
>i would assume each object has positional data
yes it does. every square has a grid position x and y.
an array[x][y] stores the id at that position
even if that wasn't there, that only changes how much of a pita it would be to get the data you need to check for borders, but not the nature of the problem.
amended the opening post, thanks -
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Wanderer über dem Nebelmeer (wandereruber@poa.st)'s status on Sunday, 30-Aug-2026 10:18:27 JST
Wanderer über dem Nebelmeer
@theorytoe sometimes what these clankers come up with ain't even half bad I just wish they would ask first.