Embed Notice
HTML Code
Corresponding Notice
- Embed this notice
翠星石 (suiseiseki@freesoftwareextremist.com)'s status on Wednesday, 16-Apr-2025 18:57:53 JST 翠星石
@SuperDicq @steph \scalebox{1.4}{$8x(x^2-\dfrac{8}{x})^{12} = x \mathlarger{\mathlarger{\sum}}_{k=0}^{12}\mybinom[1]{12}{k}(x^2)^{k}(-\dfrac{8}{x})^{12-k}$}