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    thp (thp@dosgame.club)'s status on Sunday, 19-Jan-2025 21:48:20 JSTthpthp
    in reply to
    • Jan Wildeboer 😷:krulorange:

    @jwildeboer The backslash is interpreted by the shell, the single "$" is interpreted (consumed) by make, as it tries to access a variable $" (dollar-sign, followed by double-quote). To echo a "$", you need to:

    1. Escape using "\" for the shell
    2. Escape using "$$" for make

    Note how the make output of the first file is just the line:

    echo "\

    And the second invocation gets it as:

    echo "\$"

    In conversationabout 4 months ago from dosgame.clubpermalink

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