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    GreenSkyOverMe (Monika) (greenskyoverme@ohai.social)'s status on Saturday, 21-Sep-2024 18:44:48 JSTGreenSkyOverMe (Monika)GreenSkyOverMe (Monika)
    in reply to
    • Alison Kiddle

    @alisonkiddle
    If it’s by time: 50mph.

    If it’s by distance: t1 hours * 40 mph = t2 hours * 60 mph (so t2 = 2/3 t1)
    We are looking for total distance / total time = (t1*40mi/h+t2*60mi/h)/(t1+t2)
    = 2*t1*40mi/h / (5/3 t1)
    = 80 mi/h * 3/5
    = 48 mi/h

    (I don’t know if the sign for miles is actually mi.)

    In conversationabout 8 months ago from ohai.socialpermalink
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GNU social JP is a social network, courtesy of GNU social JP管理人. It runs on GNU social, version 2.0.2-dev, available under the GNU Affero General Public License.

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