@r It depends actually.

On AMD64, if you overflow unsigned by just a bit, it overflows into a larger value anyway.

#include <stdio.h>

int main()
{
unsigned long e = 9223372036854775807 + 2;

printf("%lu\n", e);

}

main.c:6:47: warning: integer overflow in expression of type ‘long int’ results in ‘-9223372036854775807’ [-Woverflow]
6 | unsigned long e = 9223372036854775807 + 2;
| ^
翠星石 ~ $ ./a.out
9223372036854775809