@ned on R(n) formula, it may be true. but does it matter?
it just selecting radius for guiding cutter.
i also don't see why it isn't simplified... like they want it to look complex...
R(n) = (√6/2)^n = (3/2)^(n/2) = 1.5^(n/2)
@ned on R(n) formula, it may be true. but does it matter?
it just selecting radius for guiding cutter.
i also don't see why it isn't simplified... like they want it to look complex...
R(n) = (√6/2)^n = (3/2)^(n/2) = 1.5^(n/2)
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