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  1. Embed this notice
    karna :flipflop: :buffsuki: (karna@poa.st)'s status on Thursday, 24-Apr-2025 06:47:59 JST karna :flipflop: :buffsuki: karna :flipflop: :buffsuki:

    Given a rhombus and a circle inscribed inside a right triangle as per pic related. Find the radius of the circle in terms of the triangle's side lengths.

    Originally from a Michael Penn youtube video, who got it from the book Sacred Mathematics - Japanese Temple Geometry by Hidetoshi and Rothman

    #math #geometry #nigger #rape #finance

    In conversation about a month ago from poa.st permalink

    Attachments


    1. https://i.poastcdn.org/22/8a/73/228a73a52814a48f786f2b701ad115316e19be04856f2eff52edc40a2b2ac588.png
    • :ihavenomouth: likes this.
    • Embed this notice
      :ihavenomouth: (inginsub@clubcyberia.co)'s status on Thursday, 24-Apr-2025 07:03:29 JST :ihavenomouth: :ihavenomouth:
      in reply to
      @karna
      >Originally from a Michael Penn youtube video, who got it from the book Sacred Mathematics - Japanese Temple Geometry by Hidetoshi and Rothman

      this tells me that there's a simple and elegant solution. I made a mess of trigonometry though, and I don't feel like working it out.
      In conversation about a month ago permalink
    • Embed this notice
      T man :sex: :puffgiga: :puffpowerroll: (theorytoe@ak.kyaruc.moe)'s status on Thursday, 24-Apr-2025 09:18:32 JST T man :sex: :puffgiga: :puffpowerroll: T man :sex: :puffgiga: :puffpowerroll:
      in reply to
      @karna wouldnt the radius be (3/2)*b?
      considering that it appears that all triangles are similar triangles and the centroid of a triangle is {b/3,h/3} wouldnt the radius of said circle just be the centroid of the little triangle on top? (since its short leg must be b/2 tall)
      In conversation about a month ago permalink
    • Embed this notice
      T man :sex: :puffgiga: :puffpowerroll: (theorytoe@ak.kyaruc.moe)'s status on Thursday, 24-Apr-2025 09:18:52 JST T man :sex: :puffgiga: :puffpowerroll: T man :sex: :puffgiga: :puffpowerroll:
      in reply to
      • T man :sex: :puffgiga: :puffpowerroll:
      @karna wait nevermind I may be stupid
      In conversation about a month ago permalink
    • Embed this notice
      T man :sex: :puffgiga: :puffpowerroll: (theorytoe@ak.kyaruc.moe)'s status on Thursday, 24-Apr-2025 09:35:17 JST T man :sex: :puffgiga: :puffpowerroll: T man :sex: :puffgiga: :puffpowerroll:
      in reply to
      • stacksmash
      @stacksmash @karna retardtoe
      In conversation about a month ago permalink
    • Embed this notice
      stacksmash@loli.church's status on Thursday, 24-Apr-2025 09:35:18 JST stacksmash stacksmash
      in reply to
      • T man :sex: :puffgiga: :puffpowerroll:

      @theorytoe@ak.kyaruc.moe @karna@poa.st stupidtoe

      In conversation about a month ago permalink
    • Embed this notice
      a (user@ln.vapid.name)'s status on Thursday, 24-Apr-2025 14:21:37 JST a a
      in reply to
      • :ihavenomouth:
      @Inginsub @karna \frac{c(b+a-c)}{2(c+a)}, remember a rhombus is a tilted square, no trigonometry needed
      In conversation about a month ago permalink
      :ihavenomouth: likes this.
    • Embed this notice
      karna :flipflop: :buffsuki: (karna@poa.st)'s status on Saturday, 26-Apr-2025 06:46:39 JST karna :flipflop: :buffsuki: karna :flipflop: :buffsuki:
      in reply to
      • :ihavenomouth:
      • CEO of Monoeye Dating
      • T man :sex: :puffgiga: :puffpowerroll:
      • Kazak
      • hazlin no plap pirate

      the time limit is up, here's a solution with no trig nor non-elementary formulae, but with heavy use of similar triangles. here d is the side-length of the rhombus and e is the length of the vertical side of the upper triangle. In the last picture, it is hard to see but the dark purple represents the outer triangle.

      cc @Inginsub @Kazak @hazlin @theorytoe @ceo_of_monoeye_dating

      In conversation about a month ago permalink

      Attachments


      1. https://i.poastcdn.org/c6/12/b3/c612b31a8f15ef36b1db4e69529575cc2ca98f3fc4546556f88ed1b6f40719fd.png

      2. https://i.poastcdn.org/32/45/fe/3245fe7b7bb3aa899dad6aeb9b28c5b4ff7d9cde2cbf2c1c4f94c4ad1c27b369.png

      3. https://i.poastcdn.org/59/13/5d/59135d05979ff34fa8d751109938c3fad828a8ac4aeb239df4ee41659abaa040.png

      4. https://i.poastcdn.org/29/24/b7/2924b7317527a9f281e61cc86d808bf6a6c0c406a2c6c2923b392f5c2d3da032.png

      5. https://i.poastcdn.org/74/92/96/7492964751aed66209c44d41e08609eacb8ed923e9f0e985672e3f4ba73fc9a7.png

      :ihavenomouth: likes this.
    • Embed this notice
      karna :flipflop: :buffsuki: (karna@poa.st)'s status on Saturday, 26-Apr-2025 06:46:40 JST karna :flipflop: :buffsuki: karna :flipflop: :buffsuki:
      in reply to
      • :ihavenomouth:
      • Kazak

      @Kazak @Inginsub I'll post a solution tomorrow or day after but in the meantime, a big hint I can give is that drawing perpendicular lines from the center of the circle to where the circle meets the inner triangle's sides is a good first step towards getting ratios of certain lengths

      In conversation about a month ago permalink

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