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   greenshoots (greenshoots@poa.st)'s status on Wednesday, 12-Feb-2025 00:27:53 JST greenshoots

   • d
   @deprecated_ii Apologies for the long post.
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   What if it was a " i % 2 != 0 " inside the if statement? Would that have been ok? That way you'd only need one avaluation structure to fetch the odd numbers from the array.
   
   Unless the library already has a built in function to do this like an "array.nOdd(i)" that could be assigned to a new array.
   
   What would've been your answer to clean up this code? I don't know how to code, but I would like learn about this stuff from the opinion of people that do know.
   • Embed this notice
     d (deprecated_ii@poa.st)'s status on Wednesday, 12-Feb-2025 00:27:53 JST d

     in reply to
     @greenshoots the fast way to check if an integer is odd is to look at the least significant bit and see if it's a 1 or a 0. an odd number is always going to have a 1 as the least significant bit. so "if(Array[i] & 1) { do whatever };"
     
     for the sake of readability and clarity that check might be made in an "is_odd" function
     
     there's nothing "wrong" with the mod 2 method but depending on the language and how often the check is happening it might be a significant performance problem. but that's the kind of thing you shouldn't worry about until you see the problem in a performance profiler
     
     but yeah the core point is to reduce the check to a single operation that you can put any integer into
     :ihavenomouth: likes this.
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     :ihavenomouth: (inginsub@clubcyberia.co)'s status on Wednesday, 12-Feb-2025 00:31:11 JST :ihavenomouth:

     in reply to

     • d
     @deprecated_ii @greenshoots any real compiler with optimizations will turn %2 into &1
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     d (deprecated_ii@poa.st)'s status on Wednesday, 12-Feb-2025 00:36:16 JST d

     in reply to

     • :ihavenomouth:
     @Inginsub @greenshoots yeah
     
     but then there's python
     :ihavenomouth: likes this.