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   zonk (nosleep@bae.st)'s status on Monday, 20-May-2024 03:05:35 JST zonk
   
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   • narcolepsy and alcoholism :flag: likes this.
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     Paultron-3030 (paultron@poa.st)'s status on Monday, 20-May-2024 14:30:56 JST Paultron-3030

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     @BronzeAgeHogCranker @nosleep depends on the heat output of the i9, surface area and mass of the copper and temp and makeup of the surrounding media it is radiating off into
     i don't wanna do the math but it should actually be p simple if it is just straight elemental copper and you know the specifics of how it is mounted. find steady state by setting the derivative of the energy radiated by the copper to be 0 with a given known input load from the CPU then solve for the value of the copper final temperature near the border. if it's less than like 90C you're good
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     ​🇧​​🇷​​🇴​​🇳​​🇿​​🇪​​🇦​​🇬​​🇪​​🇭​​🇴​​🇬​​🇨​​🇷​​🇦​​🇳​​🇰​​🇪​​🇷​ (bronzeagehogcranker@geofront.rocks)'s status on Monday, 20-May-2024 14:30:58 JST ​🇧​​🇷​​🇴​​🇳​​🇿​​🇪​​🇦​​🇬​​🇪​​🇭​​🇴​​🇬​​🇨​​🇷​​🇦​​🇳​​🇰​​🇪​​🇷​

     in reply to
     Erm eventually it would get thermally saturated right?? You couldn't run this indefinitely
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     Paultron-3030 (paultron@poa.st)'s status on Monday, 20-May-2024 14:31:09 JST Paultron-3030

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     • Insane Jimbo
     @jimmy_insane @nosleep @BronzeAgeHogCranker T B H (to be honest) if i were goinna use a solid chunk of copper as a heat sink i'd cut in a couple of long cooling fin channels on a mill
     you could really juice up your surface area to radiate heat off with minimal mass loss
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     Insane Jimbo (jimmy_insane@berserker.town)'s status on Monday, 20-May-2024 14:31:11 JST Insane Jimbo

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     • Paultron-3030
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     @Paultron
     Maybe the form is also important due to the volume/surface ratio
     @nosleep @BronzeAgeHogCranker