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@hazlin >calculation error
1mL was defined to be 1 gram of water, but then it was realized that density of water ever so slightly differs depending on conditions, which doesn't matter for most purposes, but does matter when it comes to scientific measurements.
All calculations have error and in this case the difference between 1mL and the current gram is an excellent extremely low error.
>You get easier math, with units that are physically harder to judge.
Metric units are very easy to judge and are usually base 10 and save you from doing math in many cases - you can shove a container onto a scale, tare the scale and pour in 1kg of water and know that you got a litre almost exactly with no complex math required.
With metric, you know that 1 metre is 100 cm and 1cm in 10mm and 1000m is a kilometer - quite easy math that can physically be easily judged.
Meanwhile, good luck with inches, yards and miles.
>Requiring you to engage in math, where none should be needed.
You face that issue with US customary units rather than metric.
Trying to get almost exactly a gallon of water with a scale that does pounds is a complex mathematical task when it should be a simple one.
>use the units your ancestors used
Such ancestors did not use the current US customary units - they faced major issues with measurements never quite replicating that that continued until the US customary units were defined based off metric units and even that system causes many errors and losses.
>You don't have to do as much math, because they are sized appropriately for common applications.
Very incorrect.
25.4mm (1 in) is slightly too large for common applications - 20mm is about the right size.
Actually getting things to fit together while using inches is a very mathematically complex task, while it's easy in metric - convert to mm and add the round units together, adding 10mm, 9mm, 8mm, 6mm, 5mm, 4mm, 3mm, 2mm or 1mm here or there as required, with excellent accuracy - meanwhile the inch only really gives you 1 in (25.4mm), or 0.5 in (12.7mm), or 0.25 in (6.35mm) of accuracy to work with (which is already a calculation disaster, let alone having to face the issue of trying to use 0.333333... in with any accuracy).