@django@kowelenz.social @buschlabor@chaos.social
here you go
{\displaystyle \zeta (s)=\sum _{n=1}^{\infty }{\frac {1}{n^{s}}}={\frac {1}{1^{s}}}+{\frac {1}{2^{s}}}+{\frac {1}{3^{s}}}+\cdots }
Puniko ? (puniko@mk.absturztau.be)'s status on Wednesday, 15-Feb-2023 17:21:17 JST
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Puniko ? (puniko@mk.absturztau.be)'s status on Wednesday, 15-Feb-2023 17:21:17 JST Puniko ?