Embed Notice

HTML Code

<blockquote style="position: relative; padding-left: 55px;"><section><a href="https://mastodon.social/users/airspeedswift/statuses/114234894661520723">Ben Cohen (airspeedswift@mastodon.social)'s status on Friday, 28-Mar-2025 04:57:20 JST</a><a href="https://mastodon.social/@airspeedswift" title="airspeedswift@mastodon.social"><img src="https://gnusocial.jp/avatar/89261-48-20230718235211.webp" width="48" height="48" alt="Ben Cohen" style="position: absolute; left: 0; top: 0;">Ben Cohen</a></section><article><p>the kids are constantly having to sign forms promising they haven't used chat gpt for their homework, but I don't think they need to worry about it going undetected quite yet</p></article><footer><a rel="bookmark" href="https://gnusocial.jp/conversation/4803806#notice-9409146">In conversation</a><time datetime="2025-03-28T04:57:20+09:00" title="Friday, 28-Mar-2025 04:57:20 JST">about 14 days ago</time> <span>from <span><a href="https://mastodon.social/@airspeedswift/114234894661520723" rel="external" title="Sent from mastodon.social via ActivityPub">mastodon.social</a></span></span><a href="https://mastodon.social/@airspeedswift/114234894661520723">permalink</a><h4>Attachments</h4><ol><li><label><a rel="external" href="https://gnusocial.jp/attachment/4372825">A screenshot of a ChatGPT answer.The probability of both events happening (i.e., drawing two face cards) is:P(both face) = 12/52 * 11/51 = 3/13*11/51 = 33/663 = 1/21Event 3: Drawing two cards that are either both black or both face cards
Now, we need to find the probability that either both cards are black or both cards are face cards.Since these two events are mutually exclusive (they can't happen at the same time), we can simply add the probabilities.P(both black or both face) = P(both black) + P(both face)</a></label><br><a href="https://files.mastodon.social/media_attachments/files/114/234/894/416/508/738/original/11e3aa3f1f9735f8.png" rel="external">https://files.mastodon.social/media_attachments/files/114/234/894/416/508/738/original/11e3aa3f1f9735f8.png</a></li></ol></footer></blockquote>

Corresponding Notice

Embed this notice
Ben Cohen (airspeedswift@mastodon.social)'s status on Friday, 28-Mar-2025 04:57:20 JST Ben Cohen
the kids are constantly having to sign forms promising they haven't used chat gpt for their homework, but I don't think they need to worry about it going undetected quite yet
In conversationabout 14 days ago from mastodon.socialpermalink
Attachments
1. A screenshot of a ChatGPT answer. The probability of both events happening (i.e., drawing two face cards) is: P(both face) = 12/52 * 11/51 = 3/13*11/51 = 33/663 = 1/21 Event 3: Drawing two cards that are either both black or both face cards Now, we need to find the probability that either both cards are black or both cards are face cards. Since these two events are mutually exclusive (they can't happen at the same time), we can simply add the probabilities. P(both black or both face) = P(both black) + P(both face)
  https://files.mastodon.social/media_attachments/files/114/234/894/416/508/738/original/11e3aa3f1f9735f8.png

Public

Embed Notice

HTML Code

Corresponding Notice