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so in the first chunk of the function, it iterates through the list, looking for a match. if it finds one, it exits early. This is a "load a thing and stick it in a list of loaded things" type function, so that makes sense: don't load the same asset twice if we ask for it twice.
but then once it's not found it, it allocates a 26 byte object, which it eventually inserts into the same global linked list as the list of objects it iterated at the beginning