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@lfa Overflow is something that happens during arithmetic operations. When I set 0x80 to a char variable (assuming it's at least 8-bit wide), that variable contains exactly this value: 0x80 (or bit pattern 0b10000000). There is no overflow.

The problem arises with the operator ==, which performs a widening conversion of the variable to the "int" type, because it treats that variable as a signed value (which is implementation-dependent, which is a problem on its own), and instead of treating it as 0x80, it treats it as 0xFF80 (on 16-bit platforms) or 0xFFFFFF80 (on 32-bit platforms), because this is how widening conversion with 2's complement number representation works.