Somehow, it still feels weird to actually read hex code and understand what it is doing.
In this one, it starts with C3 22 03 as well. but this time, at 0322 there is a 31, whic means LD SP,nn
the next two bytes are 2C 0B, so it sets the stack pointer to 0B2C. then a CD ED 03, that is CALL 03ED, followed by a CD 22 0A, CALL 0A22.
So at least until this point, there is a valid code path.
It really is true what they say.
Everything is open source if you can read binary.