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p (p11@baraag.net)'s status on Monday, 30-Oct-2023 21:41:56 JST p
- on-lain ✔ᵛᵉʳᶦᶠᶦᵉᵈ
@lain
I have no idea what he's talking about, but from the data I have, my guess is, that the formula is 100% * (1 - 2^-N).
This way you'll never get more than 100%.
100% * (1 - (1 / (1 + N))) would work, too.

In conversation about a year ago from baraag.net permalink
- on-lain ✔ᵛᵉʳᶦᶠᶦᵉᵈ likes this.

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