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   Sir Nedwood - Sydney 🇦🇺 (ned@noagendasocial.com)'s status on Wednesday, 12-Jul-2023 10:11:23 JST Sir Nedwood - Sydney 🇦🇺

   If speed of light is a constant, then the equation should just be E=M, depending on the units for mass.

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     Sir Funk ?? (sophistifunk@noagendasocial.com)'s status on Wednesday, 12-Jul-2023 10:15:45 JST Sir Funk ??

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     @ned I'm not sure you've thought this through.

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     Chefs Catch (chefscatch@noagendasocial.com)'s status on Wednesday, 12-Jul-2023 10:16:06 JST Chefs Catch

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     @ned My brain just broke.

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     Sir Nedwood - Sydney 🇦🇺 (ned@noagendasocial.com)'s status on Wednesday, 12-Jul-2023 10:19:57 JST Sir Nedwood - Sydney 🇦🇺

     in reply to

     • Sir Funk ??

     @Sophistifunk how so? I mean I'm sure there is something going on that I don't understand. But to my puny brain, the more I think about it the more it makes sense.

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     Sir Funk ?? (sophistifunk@noagendasocial.com)'s status on Wednesday, 12-Jul-2023 10:27:25 JST Sir Funk ??

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     @ned firstly, because the entire point of the theory is that the equations are independent of units and always true. That's the only reason for it. Secondly, it requires defining the mass in terms of speed which subsumes distance and time both of which interact with mass, and I'm not smart enough to tell you where that fucks up the rest of the math but I'm smart enough to know it's in there somewhere. Mostly the first one.

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     Sir Funk ?? (sophistifunk@noagendasocial.com)'s status on Wednesday, 12-Jul-2023 10:41:44 JST Sir Funk ??

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     @ned if you defined one of the units you would have to define all of them, which would overcomplicate everything with conversion factors, which would then at the end have to be taken out again anyway, leaving you with e=mc^2

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     Sir Nedwood - Sydney 🇦🇺 (ned@noagendasocial.com)'s status on Wednesday, 12-Jul-2023 10:44:44 JST Sir Nedwood - Sydney 🇦🇺

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     • Sir Funk ??

     @Sophistifunk huh? no, I'm not defining units. that's the point. units are not defined. Therefor you can ignore constants. C is a constant. C^2 doubly so. If energy is dependent on C, you would need to prove that for different values of C, which we can't do.

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     Sir Funk ?? (sophistifunk@noagendasocial.com)'s status on Wednesday, 12-Jul-2023 10:50:17 JST Sir Funk ??

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     @ned e=mc^2 isn't an algorithm, it's a statement of the relationship between 3 things, regardless of their values. This is separate from C being a constant regardless of your reference frame. You're confusing special and general relativity. One is a mathematical construction atop maxwell's equations, the other is a bunch of statements about the universe we live in.

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     Sir Nedwood - Sydney 🇦🇺 (ned@noagendasocial.com)'s status on Wednesday, 12-Jul-2023 11:49:50 JST Sir Nedwood - Sydney 🇦🇺

     • 3.3

     @33over10 Is 1mph a big number? what about 38,624m/day, or 46,284,115ft/yr? The number is irrelevant. It's the relationship that matters.

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     RadarRider (radarrider@noagendasocial.com)'s status on Wednesday, 12-Jul-2023 12:55:14 JST RadarRider

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     • 3.3

     @ned @33over10

     If you increase the mass moving at the speed of light, the energy involved in moving that mass, or released when that mass strikes another object is increased by the square of the mass times the (constant, presumably) speed of light.

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     Brother Phil 🇦🇺 au (philcolbourn@noagendasocial.com)'s status on Wednesday, 12-Jul-2023 18:54:03 JST Brother Phil 🇦🇺 au

     in reply to

     @ned but that is an approximation when velocity of thing is small... from memory

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     Cook ?Syd (cook@noagendasocial.com)'s status on Wednesday, 12-Jul-2023 19:38:14 JST Cook ?Syd

     in reply to

     @ned Then you would be screwing with the metric system.