@evan If you have two protocols and that means half the potential of the network, does creating a bridge for the two protocols multiply again to get the full value of Metcalfe’s law or is bridging them still just additive? Or some other math?
@evan If you have two protocols and that means half the potential of the network, does creating a bridge for the two protocols multiply again to get the full value of Metcalfe’s law or is bridging them still just additive? Or some other math?
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